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August 12, 2008

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The Sexiest Equation Ever

Er-hem.

Robin-sig.gif
Posted August 12, 2008 at 10:46 | Comments (6) | Permasnark
File under: Briefly Noted

Comments

That graph might be sexy, but the equation is downright fugly compared to e^{i*pi} + 1 = 0, aka "Euler's identity."

Posted by: Tim on August 13, 2008 at 04:25 AM

I will not allow your pedantry to detract from the fact that y = mx + b and, apparently, fishnets.

:-)

Posted by: Robin on August 13, 2008 at 04:29 AM

See, even y = mx + b has got nothing on y - y0 = m (x - x0). Or, ooh, ooh! (x - x0)^2 + (y - y0)^2 = r^2. Oh, circle, you've got it going on. Oh, you look so good.

Posted by: Tim on August 13, 2008 at 05:15 AM

Er, sorry Tim... but I'm straight.

(I just made myself laugh SOOOO hard!)

Posted by: Robin on August 13, 2008 at 12:57 PM

Wait, now the circle is gay? I'm confused.

Posted by: Peter on August 15, 2008 at 08:02 PM

The line is straight, and Robin is homolinear.

Historically, mathematical shapes are attracted to those different from themselves: cf. The Dot and the Line,

Posted by: Tim on August 16, 2008 at 01:19 AM
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