See, even y = mx + b has got nothing on y - y0 = m (x - x0). Or, ooh, ooh! (x - x0)^2 + (y - y0)^2 = r^2. Oh, circle, you've got it going on. Oh, you look so good.

The stomping grounds of Robin Sloan, Matt Thompson, and Tim Carmody, serving up links and dish on the happenings of the day -- or back in the day -- or the days to come.

## Comments

That

graphmight be sexy, but theequationis downright fugly compared to e^{i*pi} + 1 = 0, aka "Euler's identity."I will not allow your pedantry to detract from the fact that y = mx + b and, apparently, fishnets.

:-)

See, even y = mx + b has got nothing on y - y0 = m (x - x0). Or, ooh, ooh! (x - x0)^2 + (y - y0)^2 = r^2. Oh, circle, you've got it going on. Oh, you look so good.

Er, sorry Tim... but I'm straight.

(I just made myself laugh SOOOO hard!)

Wait, now the circle is gay? I'm confused.

The line is straight, and Robin is homolinear.

Historically, mathematical shapes are attracted to those different from themselves: cf.

The Dot and the Line,